Arithmetic for the Mature Student by F. H. George
By F. H. George
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45 46 from 43/50/52/57 Your answer: 109. You are correct. You should have set the problem out like this: 1324 (1) borrowed from tens column 1215 (1) paid back to the tens column 0109 Now read 47 and you will find some further examples of subtraction on which you can practise. 47 from 46 Here are three sets of subtractions. At least one contains a mistake. Work out all the problems and find out which ones contain mistakes: 37. 3-2 16-8 130-101 8620-20 = 1 = 8 = 29 =8600 55. 34. 18-4 - 14 187-87 = 100 5209-106 = 5103 188-174 2993-1367 506-429 27331-8442 = = = = 14 1636 77 18889 48 from 39 You say that Group 3 contains a mistake.
No doubt you used the familiar long division method which looks like this: 5 87 17) 9 9 7 9 8 5 | | T~4 7 1 3 61 1 19 1 19 Make a note: the number to be divided is called the dividend, and the number used to do the dividing is called the divisor. The result is called the quotient, and what is over is called the remainder. Before we go on let us have some more practice on division.
112)3363 Clearly 112 cannot be divided (in "whole numbers" anyway) into 3 or 33, so the first number it can be divided into is 336. e. 3x112 = 336 3 30 112)3363 and nowl 12)0003 336 112 into 003 is 0, so the result (quotient) is 30, 0003 and the remainder is 3. So we have the quotient as 30, with a remainder of 3. Divide 26 into 423. The result is: 70. Quotient 16, remainder 7. 78. Quotient 7, remainder 16. 87. Quotient 9, remainder 15. 83 from 70/88/94 That is the end of this chapter. Briefly let us go over again what we have said.